8[z-(2z+8)+3]=3(z+5)

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Solution for 8[z-(2z+8)+3]=3(z+5) equation:


Simplifying
8[z + -1(2z + 8) + 3] = 3(z + 5)

Reorder the terms:
8[z + -1(8 + 2z) + 3] = 3(z + 5)
8[z + (8 * -1 + 2z * -1) + 3] = 3(z + 5)
8[z + (-8 + -2z) + 3] = 3(z + 5)

Reorder the terms:
8[-8 + 3 + z + -2z] = 3(z + 5)

Combine like terms: -8 + 3 = -5
8[-5 + z + -2z] = 3(z + 5)

Combine like terms: z + -2z = -1z
8[-5 + -1z] = 3(z + 5)
[-5 * 8 + -1z * 8] = 3(z + 5)
[-40 + -8z] = 3(z + 5)

Reorder the terms:
-40 + -8z = 3(5 + z)
-40 + -8z = (5 * 3 + z * 3)
-40 + -8z = (15 + 3z)

Solving
-40 + -8z = 15 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-40 + -8z + -3z = 15 + 3z + -3z

Combine like terms: -8z + -3z = -11z
-40 + -11z = 15 + 3z + -3z

Combine like terms: 3z + -3z = 0
-40 + -11z = 15 + 0
-40 + -11z = 15

Add '40' to each side of the equation.
-40 + 40 + -11z = 15 + 40

Combine like terms: -40 + 40 = 0
0 + -11z = 15 + 40
-11z = 15 + 40

Combine like terms: 15 + 40 = 55
-11z = 55

Divide each side by '-11'.
z = -5

Simplifying
z = -5

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